[Python] 測量片段代碼執行所需時間
- 2023.08.16
- Python
timeit timeit timeit.timeit( stmt='pass', setup='pass', timer=<default timer>, number=1000000, globals=None ) repeat timeit.repeat( stmt='pass', setup='pass', timer=<default t ...
timeit timeit timeit.timeit( stmt='pass', setup='pass', timer=<default timer>, number=1000000, globals=None ) repeat timeit.repeat( stmt='pass', setup='pass', timer=<default t ...
https://leetcode.com/problems/partition-list Solution ge_cur.next = cur ge_cur = cur → ge_cur = ge_cur.next = cur ⇒ 1. ge_cur ← cur 2. ge_cur.next ≡ cur.next ← cur ⇒ loop ge_cur.next = ge_cur = cur ⇒ ...
Naming grid is a m × n matrix m := len(grid) n := len(grid[0]) $$ grid = \left| \begin{aligned} & a_{0, 0} & \quad & a_{0, 1} & \quad & a_{0, 2} & \quad & … & \qu ...
Naming Convention Python Class and Function/Method (UpperCamelCase) Constant (CAPITALIZED_WITH_UNDERSCORES) Others (lowercase_separated_by_underscores) Underscore Before a Name (name_) Avoid Keyword C ...
https://leetcode.com/problems/the-maze Solution m := len(maze) n := len(maze[0]) Time Complexity: O(m * n) Space Complexity: O(m * n) (The input and output generally do not count towards the space com ...
https://leetcode.com/problems/kth-largest-element-in-an-array Solution n := len(nums) Time Complexity: O(n * log(k)) Space Complexity: O(k) (The input and output generally do not count towards the spa ...
https://leetcode.com/problems/check-if-there-is-a-valid-partition-for-the-array Solution n := len(nums) Time Complexity: O(3 ** n)O(n) (due to memoization) Space Complexity: O(n) (The input and output ...
math Module math.inf ∞, ≡ float(“inf”) math.prod(iterable, *, start=1) def prod(iterable, *, start=1): for element in iterable: start *= element return start math.floor(f) -> in ...
https://leetcode.com/contest/weekly-contest-358/problems/apply-operations-to-maximize-score/ First Solution (Time Limit Exceeded) Time Complexity: O(n * (A + n)) A := max(nums) n := len(nums) compute ...
https://leetcode.com/contest/weekly-contest-357/problems/find-the-safest-path-in-a-grid/ Solution 計算 min_dis (queue/BFS) m := len(grid) n := len(grid[0]) min_dis[i][j] := min([manhattan_distance((i, j ...